(x^2+4x)(x^2+4x+3)=10

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Solution for (x^2+4x)(x^2+4x+3)=10 equation:


Simplifying
(x2 + 4x)(x2 + 4x + 3) = 10

Reorder the terms:
(4x + x2)(x2 + 4x + 3) = 10

Reorder the terms:
(4x + x2)(3 + 4x + x2) = 10

Multiply (4x + x2) * (3 + 4x + x2)
(4x * (3 + 4x + x2) + x2(3 + 4x + x2)) = 10
((3 * 4x + 4x * 4x + x2 * 4x) + x2(3 + 4x + x2)) = 10
((12x + 16x2 + 4x3) + x2(3 + 4x + x2)) = 10
(12x + 16x2 + 4x3 + (3 * x2 + 4x * x2 + x2 * x2)) = 10
(12x + 16x2 + 4x3 + (3x2 + 4x3 + x4)) = 10

Reorder the terms:
(12x + 16x2 + 3x2 + 4x3 + 4x3 + x4) = 10

Combine like terms: 16x2 + 3x2 = 19x2
(12x + 19x2 + 4x3 + 4x3 + x4) = 10

Combine like terms: 4x3 + 4x3 = 8x3
(12x + 19x2 + 8x3 + x4) = 10

Solving
12x + 19x2 + 8x3 + x4 = 10

Solving for variable 'x'.

Reorder the terms:
-10 + 12x + 19x2 + 8x3 + x4 = 10 + -10

Combine like terms: 10 + -10 = 0
-10 + 12x + 19x2 + 8x3 + x4 = 0

The solution to this equation could not be determined.

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